HOW TO COMPLETE FOR FOOD FORMULATION (Formulation with Two Raw Materials)

The composition of the ingredients in the artificial feed is prepared based on the nutritional needs of each species of fish and shrimp. This composition is often called feed formulation. A good formulation means to contain all the nutrients the fish need and is economically cheap and easy to obtain so it can provide benefits.
Preparation of feed formulations mainly pay attention to the calculation of protein content value because this nutrient is the main component for growth mbuh fish. Once known protein content of the feed to be made then the next step is the calculation for components of other nutrients.
There are various ways or methods to construct feed formulations, but the most common and easy to do is the pearson's four square method, the algebraic equation method, and the worksheet method. Here are some examples of how to calculate / construct feed formulations by way of / mecode

These examples may extend themselves depending on the wishes or availability of the raw materials. FORMULATION WITH TWO RAW MATERIALS

Example
How to formulate formulas! Feed for indigo with raw material of fish meal of petek and bran. The feed is expected to contain 30% protein or 30 g of protein at every 100 g feed formulation.
Settlement by pearson's four square method
1. Look for references related to the protein content of the available feedstock and will be used, ie petek and bran fish flour. From the reference can be seen that the content of fish protein powder petek is 60% and bran 9.6%.
2. Draw a square and place the desired value of the desired protein content 30% in the middle of the square diagonal line (see figure).
3. On the left side of the square include two types of available raw materials and their protein content values. On the upper left side is a raw material that has a higher protein content value (ie fish meal), while on the lower left side is having a lower protein content value (ie bran). For more details see the following picture

Fish flour (60%) Bran (9.6%) 4. Perform calculations by subtraction for each protein content of the raw material between the larger value and the desired protein content value (which is in the middle of the diagonal line). The results are part of each component of feed ingredients (see figure).

Fish starch flour (60%) (30 - 9.6 = 20.4) Rice bran (9,6%) (60 - 30 = 30,0) 5. Perform the sum of each component of the raw material, ie 20.4 + 30.0 = 50.4.

6. The values ​​obtained are as follows.
1) The amount of raw material of petek fish meal needed is 20.4 / 50,4 x 100 g = 40,48 g or 40,48%.
2) The required amount of raw material of bran is 30.0 / 50,4 x 100 g = 59,52 g or 59,52%

Note
To prove the truth of protein content value of 30% or 30 g protein per 100 g of feed fodulation from raw material of petek fish meal for 40,48 g and bran 59,52 g is as follows.
A. The amount of protein from petek fish meal is 40.48 g x 60% = 24.29 g
B. The amount of protein from bran is 59.52 g x 9.6% = 5.71 g
C. The total amount of protein per 100 g feed formulation was 24.29 g + 5.71 g = 30.0 g

Solution by algebraic equation method
1. Look for references related to the protein content of the available feedstock and will be used, ie petek and bran fish flour. From the reference can be seen that the content of fish protein powder petek is 60% and bran 9.6%.
2. Make the uncuk variable of each standard chapter to be used ie
      X = total weight (grams) of fish meal per 100 gram feed formulation
      Y = total weight (grams) of bran per 100 grams of feed formulation
3. Based on the two variables are obtained equation 1
X + Y = 100 (equation 1)
4. Based on the value of protein content of each raw material and the desired protein value obtained equation 2
0.6 X + 0,096 Y = 30 (equation 2)
0.6 is a value of 60% (60/100) of the protein content of fish pecek; 0.096 was a value of 9.6% (9.6 / 100) of the bran protein content; 30 is the amount of protein desired for every 100 g feed formulation.
5. To get the value of one of the variables, an equation 3 is made with the basis of equation 1
      0.6 X + 0.6 Y = 60 (equation 3) (each multiplied by 0.6 so that there will be 2 equations containing the same variable value of 0.6 X) Make a deduction from the new 3 equation obtained by equation 2 So it can be obtained the value of Y is the number of grams of bran for every 100 g feed formulation.

0.6X + 0.6 Y = 60 (equation 3)
0.6 X + 0,096 Y = 30 (equation 2)
0.504 Y = 30
           Y = 30 / 0,504
                      = 59,52
6. Enter the value of Y obtained in equation 1 so that X value can be obtained, that is the number of gram of petek fish meal for every 100 g feed formulation.
X + 59.52 = 100
                  X = 100 - 59.52
                              = 40.48
Thus it can be seen that to formulate feed formulation containing 30% protein or 30 g protein for every 100 g feed formulation required material from bran (Y) as much 59.52 g and petek meal (X) of 40.48 g.